C11SEQ3 - Dãy số

Tác giả: hieult

Ngôn ngữ: C++

#include <set>
#include <map>
#include <list>
#include <cmath>
#include <queue>
#include <stack>
#include <cstdio>
#include <string>
#include <vector>
#include <cstdlib>
#include <cstring>
#include <sstream>
#include <iomanip>
#include <iostream>
#include <algorithm>

#include <ctime>
#include <deque>
#include <bitset>
#include <cctype>
#include <utility>
#include <cassert>

using namespace std;

typedef long long ll;
typedef double ld;
typedef unsigned int ui;
typedef unsigned long long ull;

#define Rep(i,n) for(int i = 0; i < (n); ++i)
#define Repd(i,n) for(int i = (n)-1; i >= 0; --i)
#define For(i,a,b) for(int i = (a); i <= (b); ++i)
#define Ford(i,a,b) for(int i = (a); i >= (b); --i)
#define Fit(i,v) for(__typeof((v).begin()) i = (v).begin(); i != (v).end(); ++i)
#define Fitd(i,v) for(__typeof((v).rbegin()) i = (v).rbegin(); i != (v).rend(); ++i)
#define mp make_pair
#define pb push_back
#define fi first
#define se second
#define sz(a) ((int)(a).size())
#define all(a) (a).begin(), (a).end()
#define ms(a,x) memset(a, x, sizeof(a))

template<class F, class T> T convert(F a, int p = -1) { stringstream ss; if (p >= 0) ss << fixed << setprecision(p); ss << a; T r; ss >> r; return r; }
template<class T> T gcd(T a, T b) { T r; while (b != 0) { r = a % b; a = b; b = r; } return a; }
template<class T> T lcm(T a, T b) { return a / gcd(a, b) * b; }
template<class T> T sqr(T x) { return x * x; }
template<class T> T cube(T x) { return x * x * x; }
template<class T> int getbit(T s, int i) { return (s >> i) & 1; }
template<class T> T onbit(T s, int i) { return s | (T(1) << i); }
template<class T> T offbit(T s, int i) { return s & (~(T(1) << i)); }
template<class T> int cntbit(T s) { return s == 0 ? 0 : cntbit(s >> 1) + (s & 1); }

typedef pair<int, int> II;

const double PI = acos(-1.0);
const double eps = 1e-9;

const int dr[] = {-1, 0, +1, 0};
const int dc[] = {0, +1, 0, -1};

const int inf = (int)1e9 + 5;
const ll linf = (ll)1e16 + 5;
const ll mod = (ll)1e9 + 7;
#define maxn 100005

ll f[maxn];

ll go(ll x){
	int a[30];
	ll res = 0;
	int run = 0;
	while(x > 0){
		a[run++] = x % 10;
		x /= 10;
	}
	sort(a, a + run);
	Rep(i, run) res = res * 10 + a[i];
	return res;
}

ll cal(ll x){
	ll t = x * 2;
	return go(t);
}

int n;

int main(){
//	freopen("in.txt", "r", stdin);
	f[1] = 1;
	For(i, 2, 100){
		f[i] = cal(f[i - 1]);
	}

	cin >> n;
	if(n < 100){
		cout << f[n];
		return 0;
	}

	int t = (n - 40) % 6 + 40;
	cout << f[t];

    return 0;
}

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